calculate the volume of a cylinder whose height is (2x-5) inches and whose base has a radius of (x-5) inches round your answer to the nearest tenth of a cubic inch
v=(1/3)hpir^2 aprox pi to 3.14 fo this problem v=(1/3)(2x-5)(3.14)(x-5)^2 v=(1/3)(2x-5)(3.14)(x^2-10x+25) v=(1/3)(3.14)(2x^3-25x^2+100x-125) v=(1/3)([tex] 6.28x^{3}-78.5x^{2}+314x-392.5 [/tex]) v=[tex] \frac{6.28x^{3}-78.5x^{2}+314x-392.5}{3} [/tex] and since we don't know what x,height, or radius or diameter or surface area or anything about the cylinder, we can't solve